Very True.

To start, If both sides equal;

Need the support of the load thru 2 legs, so load divided by 2 to get support needed per leg/support column used

>>Then divide needed support per leg by cosine of/as efficiency to target work

>>this gives the line tension necessary for that support at that cosine efficiency per leg of support

>>as example, can logically take that same line tension and multiply it by the same cosine and get back to same support per leg

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Just as can take that same line tension now and multiply by sine and get the side force per leg.

>>Shortcut = load divided by 2 x tangent of angle gives same number, from load down to 'tangent' side force quicker

>>because tangent itself is sine/cosine, so filters the cosine factor out, and leaves the sine/side force visible

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If unequal angles, from rope height on poles, would not expect a center sit of load on rope

>>but if free ranging/on pulley to self adjust would expect load to sit between 2 equally opposing side forces in this float sideways

So, if not jammed against 1 end pole from that end so low

>>would expect equal line tension angle side force to either side of pulley serving it to opposite side

>> so pulley goes to center as like bubble level, between the competing forces

>> if equal line tension, then equal angles to conjure equal force from each side of pulley, inviting wander neither way/locked.

So now back to original problem of equal supports from 2 sides, just not rope center

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If each leg of support points to 3mins after (and before) column deflections measured from 12noon pure inline position

>>18 degrees at 6 degrees per clock minute (360degrees/60mins = 6 degrees per min.)

cosine% = ~100-2-3=95% of available line tension (and length) skip -1, then use -2-3

sine% = ~ 30% of available line tension (and length) @ about 10% sine per minute in this range

linkThe sine force will pull on pole at angle to a leveraged position as measured by length from ground as pivot

>>Before 45degres 7.5mins on clock the changes in sine are most emphatic, especially at extreme from 0 sine at noon

>>in this range cosine change is most nominal change

>>this reverses after 45degrees to more nominal changes in sine and more dramatic change in cosine

>>Thus, the most dramatic change in either is coming up from it's Zer0 value, Sine at noon towards 45degrees

>>and cosine Zer0 value at 90degrees/3o'clcock/15mins then moving towards same 45degree center