At an angle pulled, the rope is weakened, but I'm not sure what you mean by %loss of lacing or X >4. Do you mean the lacing of the eye-splice? Are you saying the eye-splice handles are not solid grips?

i rather think that at an angled pulled, the tension is leverged higher in the ropes. Thereby, more tensile strength is needed or used for the same loading. i imagine that as the line is pulled straight down with the flow of gravity force, then the force on line is equal to the load. But as gravity as active force pulls down and rope goes at angle, it takes a longer route, to do the same work of carrying load so far from support as calculated by distance measured with flow of gravity. So, for a 5' drop, it now takes 6' of line. So, rope device is not inilne with pull force, but at more leverged angle, like turning wrench device with perpendicular rather than inline force.

So, a crate on a pallet, being lifted by overhead hook has line bent over hook, then down sides and hooks to pallet. But, high tension pressure at top of crate, where rope bends to come to point at hook; so to keep from crushing crate top, we place spanning bars across to reinforce. Because the angled line raises the line tension to use more of the available tensile strength, to have less tensile strength left for other tasks/ forces/ headroom. The loss of useable tensile by this model is not from strength loss of line, but rather more tension in line.

The strength loss, comes from the tight bight around support, around knot to self etc. Then, we have an inner arc and an outer arc, of the tight bight. The inner arc, would become compressed; which in a tension only device like rope, means the compressed inner bight isn't working, and only the outer arc of the tight bight is tensioned, and only it is working to carry the loading.

The stiffer the rope is, the more compressed area/ resistance to bending the inner arc of the bight has; the more weakened the rope is, as less of rope is working as tension support. Also, the larger the diameter of the rope, becomes a multiplier of this (d)effect; for the larger arc the outer arc of bight has to make/ is more stretched/ tensioned. Whereby the rope diameter on this tight bight/ bend becomes the leveraged axis/ multiplier.

Whereby, if we used flat rope/ webbing on same tight bight/ bend, there would be about Zer0 leverageable axis, given that the flat dimension was the one bent, thereby giving about Zer0 multiplier.

So anyway, the leveraged/multiplying tension force of the angle(equal and opposites of pull and support not inline/ taking longer route for same work), leads to this dividing"% (of strength) loss of lacing(knot)".

The rope must be strong enough to accomodate the multiplied tension even though the rope strength is lessened! If we constantly work the numbers to consume the available tensile of rope (after dividning it's strength under multiplied load) rope won't last long/ have less cycles to failure, and any impact or change could give failure also. So, i'd recommend rope be at least 4x the strength needed after other calculations.

Orrrrrrrrrrr something like that.